3(x^2+2x+1)+31=0

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Solution for 3(x^2+2x+1)+31=0 equation: 



3(x^2+2x+1)+31=0

We multiply parentheses

3x^2+6x+3+31=0

We add all the numbers together, and all the variables

3x^2+6x+34=0

a = 3; b = 6; c = +34;
Δ = b2-4ac
Δ = 62-4·3·34
Δ = -372
Delta is less than zero, so there is no solution for the equation

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